Farmer John has a boolean statement that is N keywords long (1 \leq N < 2 \cdot 10^5, N odd). Only true or false appear in odd positions, while only and and or appear in even positions.

A phrase of the form x\text{ OPERATOR }y, where x and y are either true or false, and \text{OPERATOR} is and or or, evaluates as follows:

x and y: This evaluates to true if both x and y are true, and false otherwise.
x or y: This evaluates to true if either x or y is true, and false otherwise.

When evaluating the statement, FJ has to take the order of precedence in Moo Language into account. Similar to C++, and takes priority over or. More specifically, to evaluate the statement, repeat the following step until the statement consists of only one keyword.

If the statement contains an and, choose any of them and replace the phrase surrounding it with its evaluation.
Otherwise, the statement contains an or. Choose any of them and replace the phrase surrounding it with its evaluation.

It may be proven that if multiple phrases can be evaluated during a given step, it does not matter which one is chosen; the statement will always evaluate to the same value.

FJ has Q (1 \leq Q \leq 2 \cdot 10^5) queries. In each query, he gives you two integers l and r (1 \leq l \leq r \leq N, l and r are both odd), and deletes the segment from keyword l to keyword r inclusive. In turn, he wishes to replace the segment he just deleted with just one simple true or false so that the whole statement evaluates to a certain boolean value. Help FJ determine if it's possible!

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Logical Moos timer 1s memory 1024MB

#8168
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Logical Moos 1s 1024MB